Question AMD's new Zen 5 chip up to 55% faster than Intel's Core i9-13900K in leaked benchmark..

IGBT

Lifer

Jul 16, 2001

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• Thursday at 10:16 AM

• #1

In the original AIDA64 interface screenshots, the test notes the score of "16x Granite Ridge HT" came just under "32x Ryzen Threadripper" in both FP32 and FP64 results. The engineering sample was also tested with a Dual-Channel DDR5 RAM configuration running at 8,000 MT/s, with timings given of 34-45-40-42. https://www.tomshardware.com/pc-com...-43E7-B01B-D1314D051DE6&utm_source=SmartBrief

 

H

Hitman928

Diamond Member

Apr 15, 2012

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• Thursday at 10:20 AM

• #2

Their source is a post in this very forum. . .

 

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Hail The Brain Slug

Diamond Member

Oct 10, 2005

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• Thursday at 10:31 AM

• #3

The charts calculations are all wrong, as well. The 9950X was roughly/close to double the speed of the 7950X. So likely more than double the speed of the 13900k.

 

moinmoin

Diamond Member

Jun 1, 2017

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• Thursday at 10:34 AM

• #4

An engineering sample of the upcoming 16-core Zen 5 AMD Ryzen 9 9950X 'Granite Ridge' processor appears to have been benchmarked in AIDA64. The results were shared by Anandtech Forum user @igor_kavinski, who cites another user as the owner of the CPU, and credited himself as simply sharing the info in his original Zen 5 speculation thread.

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The powers we wield. 🤣

 

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CouncilorIrissa

Senior member

Jul 28, 2023

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• Thursday at 11:02 AM

• #5

The anandtech_rumormill_centipede.jpg has finally looped itself over.

 

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DrMrLordX

Lifer

Apr 27, 2000

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• Thursday at 11:15 AM

• #6

CouncilorIrissa said:

The anandtech_rumormill_centipede.jpg has finally looped itself over.

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Human centipede nooooooo

Brought to you by the power of Zen5!

 

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StinkyPinky

Diamond Member

Jul 6, 2002

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• Thursday at 1:27 PM

• #7

I also like to quote myself

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I also like to quote myself.

 

bba-tcg

Senior member

Apr 8, 2010

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computerguyonline.net

• Thursday at 9:41 PM

• #8

StinkyPinky said:

I also like to quote myself.

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Well, as I've said many, many times, I never repeat myself.