I'm nipping this in the bud:
Consider the number 0.1.
This is equivalent to 10^(-1).
Then 0.01 = 10^(-2), 0.001=10^(-3), etc.
Then if there are n 0s between the decimal and the one, the number is 10^(-(n-1)), clearly.
Now we increase n arbitrarily, to 0.000...1:
lim (n->infinity)...