- Dec 26, 2002
- 22
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Originally posted by: heliomphalodon
There are several reasons.
First, 0! is defined as 1 so that certain combinatorial formulas will have simple forms.
Second, the factorial function can be extended from the integers to the entire complex plane by use of the gamma function. As I recall, this leads to a definition of z! = gamma(z+1) for all complex z (except for z=0, -1, -2, -3,...). Since gamma(1)=gamma(2)=1 we have 0!=1.
Originally posted by: MrDudeMan
Originally posted by: heliomphalodon
There are several reasons.
First, 0! is defined as 1 so that certain combinatorial formulas will have simple forms.
Second, the factorial function can be extended from the integers to the entire complex plane by use of the gamma function. As I recall, this leads to a definition of z! = gamma(z+1) for all complex z (except for z=0, -1, -2, -3,...). Since gamma(1)=gamma(2)=1 we have 0!=1.
wow
Originally posted by: heliomphalodon
There are several reasons.
First, 0! is defined as 1 so that certain combinatorial formulas will have simple forms.
Second, the factorial function can be extended from the integers to the entire complex plane by use of the gamma function. As I recall, this leads to a definition of z! = gamma(z+1) for all complex z (except for z=0, -1, -2, -3,...). Since gamma(1)=gamma(2)=1 we have 0!=1.
With all due respect, I don't think that helps -- one could just as sensibly say that the empty set has zero permutations.Originally posted by: KillerCow
A set of 0 things has 1 permutation... the permutation of nothing.
so 0! = 1
With all due respect, I don't think that helps -- one could just as sensibly say that the empty set has zero permutations.
Originally posted by: KillerCow
With all due respect, I don't think that helps -- one could just as sensibly say that the empty set has zero permutations.
No, it has one: the empty set.
Originally posted by: heliomphalodon
There are several reasons.
First, 0! is defined as 1 so that certain combinatorial formulas will have simple forms.
Second, the factorial function can be extended from the integers to the entire complex plane by use of the gamma function. As I recall, this leads to a definition of z! = gamma(z+1) for all complex z (except for z=0, -1, -2, -3,...). Since gamma(1)=gamma(2)=1 we have 0!=1.
Originally posted by: KillerCow
With all due respect, I don't think that helps -- one could just as sensibly say that the empty set has zero permutations.
No, it has one: the empty set.