2 + 2 = 5 for extremely large values of 2.

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Sp33d

Member
Feb 13, 2005
181
0
0
2+2 could equal 5 if you were dealing with fourth dimension techniques. A hypercube (a square in the fourth demension) is made up of a limitless number of smaller cubes all fused together at a single point, creating an outside that is inside, depending on your viewpoint. When dealing with a hypercube, if the edge of one of the smaller cubes is 2, the edge of the hypercube will be 2^i*e, because you go out of the realm of real numbers in the fourth dimension. So....if pi*i=e, then i*e=pi*i*i, which brings you into a state of vacuum, and makes the answer everything, i.e infinity. Therefore, this could be a true solution if you were dealing with the fourth dimension.

 

JAGedlion

Member
Jun 13, 2004
34
0
0
I wish I could remember it, my math teacher in highschool showed us the (maybe just a, but I think its the same one) 2+2=5 proof considering we had 2+2=5 for large values of 2 in those exact words. Its not really a proof becuase like all those divide by zero tricks it involves doing bad math and was meant to demonstrate something about limits (you violated some limit rule). Wish I could remember the 'proof'.
 

Matthias99

Diamond Member
Oct 7, 2003
8,808
0
0
Originally posted by: Sp33d
2+2 could equal 5 if you were dealing with fourth dimension techniques. A hypercube (a square in the fourth demension) is made up of a limitless number of smaller cubes all fused together at a single point, creating an outside that is inside, depending on your viewpoint. When dealing with a hypercube, if the edge of one of the smaller cubes is 2, the edge of the hypercube will be 2^i*e, because you go out of the realm of real numbers in the fourth dimension. So....if pi*i=e, then i*e=pi*i*i, which brings you into a state of vacuum, and makes the answer everything, i.e infinity. Therefore, this could be a true solution if you were dealing with the fourth dimension.

A hypercube is made of a finite number of cubes (8, to be exact), which in no way are "fused together at a single point", and has a well-defined finite volume in either 4- or 3-space (well, at least, you can measure the volume of the immersion in 3-space). Multidimensional geometry has nothing to do with imaginary numbers. Also, pi * i != e (I don't know what (pi * i) is off the top of my head, but it's definitely an imaginary number, which e is not).

Please don't spew math-related crap that you don't understand. It just confuses other people.
 

Gibson486

Lifer
Aug 9, 2000
18,378
1
0
I remember in my differential equation class, my prof had a proof. It was 1=0. Appearently, it was discrete math. Math can be funny sometimes.
 

dashiki

Senior member
Jan 24, 2005
247
0
0
My prof did the same thing discrete math is weird. my wife got her degree in math and I swear her 500 level courses they were just making sh1t up as they went.
 

Emultra

Golden Member
Jul 6, 2002
1,166
0
0
De facto, 2 + 2 = 5 if a powerful enough government says it is.

Like the ones that all the countries in the world have, or will have soon.
 
Jun 9, 2005
104
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Originally posted by: SniperFury
Fusion. It is how the sun operates. 2 + 2 = 5 if I remember correctly, it was a while back I may even have it messed up. Like a wrong value here or there

i thought the sun worked by 1+1+1+1=1???
 

mdchesne

Banned
Feb 27, 2005
2,810
1
0
Originally posted by: imgod2u
The expression 2 + 2 = 5 is from George Orwell's 1984 as far as I know. There are probably tons of impressive-sounding proofs for this. Not sure whether any of them are credible though...

actually, it's part of the gestalt theory where the sum is greater than the parts. *the more you know* lol
 

piroroadkill

Senior member
Sep 27, 2004
731
0
0
This comes back to the old 0.99999999999999999999999999999999999999999999999999999999999999999999999 recurring = 1 argument.

You're talking about precisely the same thing here.
 

eilute

Senior member
Jun 1, 2005
477
0
0
It might be a programming reference. Below is some code in a semi-generic syntax.

int = A;
int = B;
int = C;

C = A + B;

if (A = 2.6 and B = 2.1),
C= 5;

The idea here is that the computer thinks that the numbers A, B, and C are all integers. When A is set to the value 2.6 the computer rounds it to 3. Likewise, when the variable B is set to 2.1 the computer rounds it to 2. If the values of A and B are added together then the value of C = A + B is 5.






 
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