A ArJuN Platinum Member Aug 13, 2005 2,816 0 76 May 28, 2006 #26 Originally posted by: StrangerGuy At first glance x must be greater than 1 and less than 2. EDIT: 49^x = 343 7^(2x) = 7^3 2x = 3 x = 1.5 Click to expand... QFT That's the proper way to do it.
Originally posted by: StrangerGuy At first glance x must be greater than 1 and less than 2. EDIT: 49^x = 343 7^(2x) = 7^3 2x = 3 x = 1.5 Click to expand... QFT That's the proper way to do it.
U Udel Senior member Sep 2, 2005 892 0 0 May 28, 2006 #27 Originally posted by: bonkers325 49^x = 343 log(49)^x = log(343) xlog(49)=log(343) x=log(343)/log(49) x=1.5 Click to expand... :thumbsup:
Originally posted by: bonkers325 49^x = 343 log(49)^x = log(343) xlog(49)=log(343) x=log(343)/log(49) x=1.5 Click to expand... :thumbsup:
S Special K Diamond Member Jun 18, 2000 7,098 0 76 May 28, 2006 #28 Originally posted by: Udel Originally posted by: bonkers325 49^x = 343 log(49)^x = log(343) xlog(49)=log(343) x=log(343)/log(49) x=1.5 Click to expand... :thumbsup: Click to expand... EDIT: n/m I see it
Originally posted by: Udel Originally posted by: bonkers325 49^x = 343 log(49)^x = log(343) xlog(49)=log(343) x=log(343)/log(49) x=1.5 Click to expand... :thumbsup: Click to expand... EDIT: n/m I see it
S StevenYoo Diamond Member Jul 4, 2001 8,628 0 0 May 28, 2006 #29 Originally posted by: Udel Originally posted by: bonkers325 49^x = 343 log(49)^x = log(343) xlog(49)=log(343) x=log(343)/log(49) x=1.5 Click to expand... :thumbsup: Click to expand... yep, that's how i did it
Originally posted by: Udel Originally posted by: bonkers325 49^x = 343 log(49)^x = log(343) xlog(49)=log(343) x=log(343)/log(49) x=1.5 Click to expand... :thumbsup: Click to expand... yep, that's how i did it