Evadman
Administrator Emeritus<br>Elite Member
- Feb 18, 2001
- 30,990
- 5
- 81
Yea, um no way in hell.
Math #1
((9.8N * 30Kg) * 0.5M) * 9 = 1323 Joules per pushup at a normal person's efficency of 10%.
1323J * 50 pushups/min = 66150 Joules/minute
1 joule = 0.00239 Calories
66150 * 0.00239 = 158.09 calories/minute
158.09 Cal * 200 minutes = 31618 Calories or 3161800 calories (small C)
31618 calories / 2500 calories = 12.64 lbs of weight lost (1 lb of fat = 2500 calories)
More Math
it takes 1 calorie (little C) to raise 1 gram of water 1 degree C.
3161800 calories / (36 Kg * 1000) = 878.2 degrees C
Even More math
1 watt = 1 joule/second
66150 Joules/minute / 60 = 1102.5 watts
So if he did 10,000 pushups he would have lost about 12.64 lbs of body mass in that 200 minutes. Also, his body produced the equivelent of 3.3 kilowatt hours of electricity. My house uses less. Assuming his body is 100% water, that is enough calories to raise the tempeature of 30Kg of water by 878.2 degrees.
Math #1
((9.8N * 30Kg) * 0.5M) * 9 = 1323 Joules per pushup at a normal person's efficency of 10%.
1323J * 50 pushups/min = 66150 Joules/minute
1 joule = 0.00239 Calories
66150 * 0.00239 = 158.09 calories/minute
158.09 Cal * 200 minutes = 31618 Calories or 3161800 calories (small C)
31618 calories / 2500 calories = 12.64 lbs of weight lost (1 lb of fat = 2500 calories)
More Math
it takes 1 calorie (little C) to raise 1 gram of water 1 degree C.
3161800 calories / (36 Kg * 1000) = 878.2 degrees C
Even More math
1 watt = 1 joule/second
66150 Joules/minute / 60 = 1102.5 watts
So if he did 10,000 pushups he would have lost about 12.64 lbs of body mass in that 200 minutes. Also, his body produced the equivelent of 3.3 kilowatt hours of electricity. My house uses less. Assuming his body is 100% water, that is enough calories to raise the tempeature of 30Kg of water by 878.2 degrees.