After thinking about your response some, I know where I went wrong. Using permutation, you can't get combinations that use repititive pairs, e.g.Originally posted by: SWScorch
2^6 implies you can arrange the bits any way you see fit. But with 4 2-bit numbers, those two bits always stay side-by-side, so it's not really 6 independent bits.
Originally posted by: SomeDude22
remember .999999999999999999999999999999999999999999999999999999999999999999999999999999
999=1