- Aug 29, 2004
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I am a bit confused here and need a little push,
1111 = 15
1111 1111 = 255
1111 1111 1111 = 2815? OR 270
the first set of bits goes to a highest value of 15, the first and second set goes to 255. now I am lost at what does the third set make, does the rightmost bit position equat to 1, 0 or does it go to 256
I know this is a bit confusing and I have searched my textbook and the sets of bits they give are all done in sets of 8, I am working with a set of 12, please any help would be greatly appreciated
1111 = 15
1111 1111 = 255
1111 1111 1111 = 2815? OR 270
the first set of bits goes to a highest value of 15, the first and second set goes to 255. now I am lost at what does the third set make, does the rightmost bit position equat to 1, 0 or does it go to 256
I know this is a bit confusing and I have searched my textbook and the sets of bits they give are all done in sets of 8, I am working with a set of 12, please any help would be greatly appreciated