Originally posted by: crazeinc
S = integration sign
S(x+2)/(x^2+4x+1) dx
u= x^2+4x+1
du = 2x+4
1/2 S du/u dx
1/2 ln |u| + c
1/2 ln |(x^2+4x+1)| + c
yes, no? I'm drawing a blank.
Originally posted by: otispunkmeyer
Originally posted by: crazeinc
S = integration sign
S(x+2)/(x^2+4x+1) dx
u= x^2+4x+1
du = 2x+4
1/2 S du/u dx
1/2 ln |u| + c
1/2 ln |(x^2+4x+1)| + c
yes, no? I'm drawing a blank.
yeh thats right i think
you can also do it partial fractions style by factorising the bottom and putting each term under A and B but since the top is a derivative of the bottom you can skip that
Originally posted by: otispunkmeyer
Originally posted by: crazeinc
S = integration sign
S(x+2)/(x^2+4x+1) dx
u= x^2+4x+1
du = 2x+4
1/2 S du/u dx
1/2 ln |u| + c
1/2 ln |(x^2+4x+1)| + c
yes, no? I'm drawing a blank.
yeh thats right i think
you can also do it partial fractions style by factorising the bottom and putting each term under A and B but since the top is a derivative of the bottom you can skip that
Originally posted by: otispunkmeyer
Originally posted by: otispunkmeyer
Originally posted by: crazeinc
S = integration sign
S(x+2)/(x^2+4x+1) dx
u= x^2+4x+1
du = 2x+4
1/2 S du/u dx
1/2 ln |u| + c
1/2 ln |(x^2+4x+1)| + c
yes, no? I'm drawing a blank.
yeh thats right i think
you can also do it partial fractions style by factorising the bottom and putting each term under A and B but since the top is a derivative of the bottom you can skip that
sorry u cant do partial fractions because of the 1
(X^2 + 4X + 1) cant be factorised since to get a 1 you need a 1 and a 1, but then (x+1)(x+1) = x^2 + 2x +1
Originally posted by: chuckywang
Originally posted by: otispunkmeyer
Originally posted by: otispunkmeyer
Originally posted by: crazeinc
S = integration sign
S(x+2)/(x^2+4x+1) dx
u= x^2+4x+1
du = 2x+4
1/2 S du/u dx
1/2 ln |u| + c
1/2 ln |(x^2+4x+1)| + c
yes, no? I'm drawing a blank.
yeh thats right i think
you can also do it partial fractions style by factorising the bottom and putting each term under A and B but since the top is a derivative of the bottom you can skip that
sorry u cant do partial fractions because of the 1
(X^2 + 4X + 1) cant be factorised since to get a 1 you need a 1 and a 1, but then (x+1)(x+1) = x^2 + 2x +1
QFT! Technically you can do partial fractions, since the roots are real. However, it would be a bitch cause the roots are not nice. OP did it the way the calc textbooks want you to. Just remember, if it's too hard, you're probably doing it wrong.
Originally posted by: crazeinc
I have a test in six hours, unfortunately. These calculus classes really have been a miserable experience. If you actually like doing this stuff, please let me know your secret, because I was thinking about continuing with calc 3 in the fall because I like to watch my hair recede.