R RobDowneyJr Member Feb 17, 2003 141 0 0 May 29, 2003 #1 the derivative of x^x = x^x(ln (x) +1) can anyone explain why
D dighn Lifer Aug 12, 2001 22,820 4 81 May 29, 2003 #2 x^x = e^(xlnx) d/dx = d/dx =(e^(xlnx))*(1+lnx) =x^x(1+lnx)
hdeck Lifer Sep 26, 2002 14,530 1 0 May 29, 2003 #4 see, calculus is much easier than people make it out to be
R RobDowneyJr Member Feb 17, 2003 141 0 0 May 29, 2003 #5 how about this: lim (1+x)^(1/x) x->0 can you explain why its e?