- Jun 22, 2001
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Ok, I was playing some American roulette (has the 0 and 00's) the other day and thought of a possible good way to win, but I know that there's probably a catch and am having trouble figuring out some odds.
There are 38 numbers, and 1-36 is split into 3rd's at 2:1 odds. If you cover 2/3rd's of the numbers, that's 24/38 = 63.157%. At 2:1 odds, you will net a bet (say $5). Somehow I don't think that you would have a 63% chance of netting a bet, and that since the 0 and 00's are their own "sections" altogether that somehow screws up your odds of netting a bet. So it's probably not 63% at 2:1 odds, but what would your true chance of winning be?
There are 38 numbers, and 1-36 is split into 3rd's at 2:1 odds. If you cover 2/3rd's of the numbers, that's 24/38 = 63.157%. At 2:1 odds, you will net a bet (say $5). Somehow I don't think that you would have a 63% chance of netting a bet, and that since the 0 and 00's are their own "sections" altogether that somehow screws up your odds of netting a bet. So it's probably not 63% at 2:1 odds, but what would your true chance of winning be?