- Jul 13, 2004
- 52
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Hopefully someone here enjoys this stuff. I've been trying to get it to work out for like 30 minutes now.
Reiman Sums
2x^2 + 10 on the interval [0,12]
Using the fundamental theory of calculus gives 1272 as the answer, that is the correct answer.
Teacher wants to see it done with Reiman Sum, I can't get the answer doing it that way.
I followed the steps, my only doubt is where you turn k^2 into n(n+1)(2n+1) divided by 6.
Your then supposed to take the limit of and get a number as n approaches infinity.
So right now I have:
192 * (2n^2+3n+1)/(n^2) + 120
In order to get 1272 I need to get 192 * 6 + 120 = 1272. How do I know that the middle section gives 6 as n approaches infinity?
Reiman Sums
2x^2 + 10 on the interval [0,12]
Using the fundamental theory of calculus gives 1272 as the answer, that is the correct answer.
Teacher wants to see it done with Reiman Sum, I can't get the answer doing it that way.
I followed the steps, my only doubt is where you turn k^2 into n(n+1)(2n+1) divided by 6.
Your then supposed to take the limit of and get a number as n approaches infinity.
So right now I have:
192 * (2n^2+3n+1)/(n^2) + 120
In order to get 1272 I need to get 192 * 6 + 120 = 1272. How do I know that the middle section gives 6 as n approaches infinity?