witeken
Diamond Member
- Dec 25, 2013
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Intel used that graph to show that they're committed to continue Moore's law, and even at a faster pace than today, while 'competitors' (TSMC) are stagnating (upper left graph):1. Five of the eight points are marked as "Forecast", even choosing words like "actual" or "data" is inappropriate for something like this. Not to mention we don't see a scale, not even a description for the Y axis, other than log scale. There is the old conundrum of whether logarithms should have units or not. I seem to remember I was taught to normalize units (off) before applying the logarithm function, so we can't have units as description, I guess. Well I had to infer that the Y-Axis denotes "area" from the slide title. But which area still remains vague, is it area to place a certain IC or is it just trivial Y = X² area of a square, that shrinks as you shorten the sides. I lean toward the latter.
2. What does the chart set out to show for the immediate future, with it's completely convoluted way to present data, It shows that 14nm is more dense than 16nm. Wow, guess what node also would be more dense than 16nm?
A. 15nm
B. 14nm
D. 13nm
E. 12nm
F. All of the above
Your graph isn't based on the number (e.g. 14nm < 16nm) but on real forecasts from Intel and TSMC.
Because they want to catch up with Intel (or at least make it look like that), so they do 16nm 1 year after 20nm. But in fact 16nm is just 20nm, but the planar transistors are replaced with FinFETs.3.Typically every node shrink is chosen such, that it basically halves the area. Twice as many transistors for the same area hence Moore's law and all that. This would read as 50% ahead in the chart presumably(?).
Intel's chart shows TSMC's [20] and [16] nodes at about the same hight. Why would TSMC go from 20 to 16ff if there is no area / no cheaper production to recoup the investments to be gained?
Yes, but as you can see from Intel's graph, 16nm won't bring a lot of improvements, so Intel will have 10nm for almost 2 years before TSMC has another transistor shrink with 10nm. By then, Intel will have 7nm. Intel's point is that their equivalent node to TSMC's (e.g. 16nm and 14nm, 10nm and 10nm) will have a smaller area and also Intel will be 1 node ahead of TSMC, so Intel should have a huge advantage (equivalent to 2 nodes) on TSMC.Also according to this graph the upcoming 14 nm process will only be 35% ahead of TSMCs 20 nm. Which should be good news for TSMC, since they both should arrive at the same time.