Originally posted by: SpunkyJones
All 0's in the network portion would be a network with a first octet of 0, which is invalid. First valid network is 1.0.0.0, or 00000001
All 1's in the network portion would be a network starting with 255 for the first octet, which is a class E network, which is an invalid network for ip addressing. It is used for experimental purposes.
Originally posted by: syco83
that wasn't the right answer
Originally posted by: n0cmonkey
Originally posted by: syco83
spunky jones got it right
Did you get an A?
Originally posted by: gcbrowni
Now explain how /31's work and why the lower /64 of an IPv6 address can't be all 0's.
Originally posted by: Goosemaster
Originally posted by: gcbrowni
Now explain how /31's work and why the lower /64 of an IPv6 address can't be all 0's.
31's will give you 0 hosts.....!!??!?
Originally posted by: spidey07
Originally posted by: Goosemaster
Originally posted by: gcbrowni
Now explain how /31's work and why the lower /64 of an IPv6 address can't be all 0's.
31's will give you 0 hosts.....!!??!?
you can use them for WAN circuits where there are only two hosts. In this case there is no need for a subnet broadcast.
-ps- hey NOC, he said "network" portion of a IPv4 address, not host.
An IPv6 address can be all 0's in the lower 64 bits. A subnet-router anycast address is an IPv6 address that has the interface ID set to all 0's. For all IPv6 addresses that start with a value other than b'000', the interface ID is 64 bits in length. So, for all IPv6 addresses that start with anything other than b'000', an address with the lower 64 bits set to 0's is a subnet-router anycast address.Originally posted by: gcbrowni
Now explain how /31's work and why the lower /64 of an IPv6 address can't be all 0's.