Is one over infinity zero?

[txrandom]

Originally posted by: JohnCU
for all intents and purposes it is 0, atleast that's what we call it in my major. f the math people.

Yah, that's what Calculus 2 for Engineers taught me. May be different in the other Calculus 2s.

 

[jman19]

Originally posted by: JohnCU
for all intents and purposes it is 0, atleast that's what we call it in my major. f the math people.

no math people would mean no engineering people

 

[cKGunslinger]

Originally posted by: txrandom
1/infinity = 0 /thread

How the fvck do you divide by thread?

 

[Stuxnet]

Originally posted by: cKGunslinger

Originally posted by: txrandom
1/infinity = 0 /thread

How the fvck do you divide by thread?

Oh gosh... someone get the stitches... my side just split open.

dividebysarcasm

 

[cKGunslinger]

Originally posted by: jbourne77

Originally posted by: cKGunslinger

Originally posted by: txrandom
1/infinity = 0 /thread

How the fvck do you divide by thread?

Oh gosh... someone get the stitches... my side just split open.

dividebysarcasm

Have a You'll feel better in no time.

 

[dullard]

The answer is yes. For all practical purposes, it is equal to zero.

 

[fitzov]

One over infinity doesn't make any sense, mathematically.

 

[sao123]

Originally posted by: fitzov
One over infinity doesn't make any sense, mathematically.

One over infinity only makes sense if
by one you actually meant Seven, and didnt finish the top correctly. 1 -> 7
and by over, you mean "on top of"
and by infinity, you mean "me", then in this context your statement might make sense.

 

[mercanucaribe]

Originally posted by: magomago

Originally posted by: UncleWai
The limit of 1/x as x approaches infinity is 0.
It never reaches zero, the bound is zero.

Its practically zero. make it .00000000000000000000000000000000000000000001 there will be no real world difference.

This is what sets apart engineers from scientists...

.9999999repeating + 1/infinity = 1 right?

If you say that .99999repeating is 1, then how can you say that 1/infinity approaches 0 instead of saying that it IS 0?

 

[fitzov]

If you say that .99999repeating is 1, then how can you say that 1/infinity approaches 0 instead of saying that it IS 0?

I think someone else answered that question in discussing limits--so I'll not repeat it.

 

[mordantmonkey]

Originally posted by: Locut0s
1/infinity is undefined. What you are thinking of is the limit Lim 1/x as x->infinity which is zero. NOT the same thing.

ding ding ding