Man as much as i hate to post in OT about my discreet math problem ..
but i can't figure it out and it is bugging the crap out of me ...
well here it is ...
How many different solutions to the equation X1+X2+X3+X4+X5+X6 = 149
ARE THERE IF THE VALUE OF EACH VARIABLE x1, x2, x3, x4, x5, x6 must be either 0 or 1 .
I think the answer is 0 or impossible .. but there might be some trick involve in it..
and that's wat been bugging me for half hour .....ARGGHhh
wat do you think ?
but i can't figure it out and it is bugging the crap out of me ...
well here it is ...
How many different solutions to the equation X1+X2+X3+X4+X5+X6 = 149
ARE THERE IF THE VALUE OF EACH VARIABLE x1, x2, x3, x4, x5, x6 must be either 0 or 1 .
I think the answer is 0 or impossible .. but there might be some trick involve in it..
and that's wat been bugging me for half hour .....ARGGHhh
wat do you think ?