LTC8K6
Lifer
- Mar 10, 2004
- 28,520
- 1,575
- 126
How is the conveyor applying force to the plane?
It must apply a force to the plane to keep the plane from moving forward.
It must counter the engine's thrust, or the plane will move.
The only contact the conveyor has with the with the plane is at the wheels.
The wheels are free to spin.
The conveyor cannot exert much force on the plane at all.
Almost 100% of the conveyor's force will be lost to wheel rotation.
If we had magic perfect frictionless bearings, 100% of the force would be lost.
In reality, there is a little force, because we don't have perfect bearings, but that's it.
The plane's engine can easily overcome wheel bearing friction.
We know this because wheel bearing friction is basically all the plane has to overcome to take off on a runway.
If you want to pick nits, there is a little friction we are leaving out, and that is the tire's rolling resistance, and the tire's grip on the surface.
These are all small though, and will not change the outcome. They are the same things the engine has to overcome on a normal takeoff.
It must apply a force to the plane to keep the plane from moving forward.
It must counter the engine's thrust, or the plane will move.
The only contact the conveyor has with the with the plane is at the wheels.
The wheels are free to spin.
The conveyor cannot exert much force on the plane at all.
Almost 100% of the conveyor's force will be lost to wheel rotation.
If we had magic perfect frictionless bearings, 100% of the force would be lost.
In reality, there is a little force, because we don't have perfect bearings, but that's it.
The plane's engine can easily overcome wheel bearing friction.
We know this because wheel bearing friction is basically all the plane has to overcome to take off on a runway.
If you want to pick nits, there is a little friction we are leaving out, and that is the tire's rolling resistance, and the tire's grip on the surface.
These are all small though, and will not change the outcome. They are the same things the engine has to overcome on a normal takeoff.