yeah, but you would be easier to tip over, no?
idk anything about this shit, but it seems like you guys are overcomplicating it
Overbuild. Solves all questions.
yeah, but you would be easier to tip over, no?
idk anything about this shit, but it seems like you guys are overcomplicating it
IMO, that's way too far to span across the front without some kind of center support.
Knee brace like this?her209:
the front needs an intermediate support, or you need to use a 2x6 instead of a 2x4. an intermediate support or a chevron brace ( looks like this /\ ) to act as a center support will work as well.
edit: or just add a knee brace at the corners of the front frame
Add it where?With that ┐cross-section (right side view) and some quick calculations, the front could bow as much as 0.15". Add another 2x4 to get a rectangular cross-section measuring 4" wide and 6" high and that should take care of the bowing.
Knee brace like this?
Yeah, the tank is supported along 3 of the 4 edges. Front and both sides. The back edge isn't supported because the holes drilled on the bottom are too close to the edge and adding some support would hit the bulkhead.yes, like that. i suppose you want it this way so that the front is accessible? if you're sticking with 2x4's, get decent quality species like doug fir or southern pine, and not some low grade furring studs.
do you intend to support your aquarium along the edges? is your aquarium capable of handling those stresses? does it need a flat surface to bear on?
Yeah, the tank is supported along 3 of the 4 edges. Front and both sides. The back edge isn't supported because the holes drilled on the bottom are too close to the edge and adding some support would hit the bulkhead.
Edge that isn't supported would be the back:
I think you should just get some W8X31
You're right - it's definitely not statistically indeterminate. However, it is statically indeterminate. You can decide any load distribution you want by assuming a solution, but that doesn't make it physically realistic, much less mathematically correct. How many reaction forces are we looking at? How many equilibrium equations can you write? The former is greater than the latter, so the problem is statically indeterminate. It's one thing to be ignorant, but it's another to tell someone else that they are wrong when you don't have the slightest notion what they're talking about. While the OP might get lucky and get away with the nonsense you suggest by sheer luck, are you going to foot the bill when your design inevitably fails? If not, quit pretending to know that which you do not.I don't think it's statistically indeterminate. I'm pretty certain, just did resource checking and this can theoretically be solved.
The load distribution is from stats, and the forces can be derived with newton's 2nd law.
I'm thinking it is like as Skorpio said, 25/25/12.5*4. Some quick calcs assuming his stand weights 25kg, fish tank 600kg.
F= ma = 0
F = 5886N + 245.3N = 6131.3N
front 2 legs @25%: 1533N downward force
back 4 legs @12.5%: 766N downward force
Really, you're a civil engineer and your only contribution is less helpful than that of a chemical engineer? I already said it's statically indeterminate. He could treat the bottom of the tank as a simply supported plate and go from there, but that's a lot more analysis than anyone here is going to do on a weekend.Really? I'm the only civil engineer here?
It's technically indeterminate on one side, but like any engineering problem, there are so many assumptions/tips/tricks to solve it and get it close enough.
Please go talk to a carpenter. You're playing with 1200lb. Depending on how long your legs are, how well you reinforced everything, x6 2x4 pieces of wood may be pushing it.