letdown427
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- Jan 3, 2006
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completely irrelevant of x? what are you on. read it again. and again. until you realise, and THEN you will feel as dumb as you are making yourself look.
Originally posted by: letdown427
completely irrelevant of x? what are you on. read it again. and again. until you realise, and THEN you will feel as dumb as you are making yourself look.
Originally posted by: letdown427
they actually did a pretty good job of wording it in my opinion, as even after 6 pages, we're still reading things into it.
"It is then possible to get the plane to move the opposite direction of the conveyor so that to an observer, the airplane doesn't move." yes, and then, you can increase the thrust from the engines, and get the plane to move a bit more.
the state you referred to is when the constant frictional force provided by the conveyor is equal to the thrust of the engines. you said yourself the fricional force is constant, and that is what provides the --> force, thrust provdiing the <-- force. so pilot can then increase thrust, to saaay, <----- force, and friction is still only ->> force, as it is constant, as you said. plane moves faster. plane continues to move faster, at a rate governed by the resultant force, which will equal force due to thrust minus resistance from the conveyor. this reultant force is of course = to the mass of the plane multiplied by the acceleration, and as this resultant force is now >0 (as thrust is bigger than resistance) the acceleration is equal to this resultant force divided by the planes mass. even if this is very small, it is acceleration. and as such, the plane will eventually reach the speed necessary for it to take off.
Originally posted by: letdown427
completely irrelevant of x? what are you on. read it again. and again. until you realise, and THEN you will feel as dumb as you are making yourself look.
Originally posted by: KillerCharlie
Originally posted by: letdown427
they actually did a pretty good job of wording it in my opinion, as even after 6 pages, we're still reading things into it.
"It is then possible to get the plane to move the opposite direction of the conveyor so that to an observer, the airplane doesn't move." yes, and then, you can increase the thrust from the engines, and get the plane to move a bit more.
the state you referred to is when the constant frictional force provided by the conveyor is equal to the thrust of the engines. you said yourself the fricional force is constant, and that is what provides the --> force, thrust provdiing the <-- force. so pilot can then increase thrust, to saaay, <----- force, and friction is still only ->> force, as it is constant, as you said. plane moves faster. plane continues to move faster, at a rate governed by the resultant force, which will equal force due to thrust minus resistance from the conveyor. this reultant force is of course = to the mass of the plane multiplied by the acceleration, and as this resultant force is now >0 (as thrust is bigger than resistance) the acceleration is equal to this resultant force divided by the planes mass. even if this is very small, it is acceleration. and as such, the plane will eventually reach the speed necessary for it to take off.
Yeah, so we agree on the physics of the problem and just disagree on the wording of the problem. I took the problem to mean that you are sitting at the gates looking out the window. Outside is a plane sitting on a conveyor. The conveyor increases its speed and the plane increases engine power such that the plane doesn't move from your perspective.
The only reason this is so widely circulated and argued about is because the question is too ambiguous.
(Oh, and I have one minor detail to nitpick--you said the plane, even with very little force, will eventually reach takeoff speed. This isn't true because drag increases with speed and you need a certain amount of thrust to overcome the drag at the required velocity for takeoff.)
Originally posted by: LoKe
Originally posted by: letdown427
completely irrelevant of x? what are you on. read it again. and again. until you realise, and THEN you will feel as dumb as you are making yourself look.
I don't feel dumb. I don't pretend to be some king of math. I'm pointing out the flaw in your arguement and am asking where you got the divide by 99 crap. If you're using 99 because it's 0.999, then why not use 88 because it's 0.888
If you can explain this to me, and use real proof, I'll admit you're right.
Originally posted by: letdown427
loke mate, the bit u put in bold is where you are wrong. hilariously.
0.8888888888... = x
100 . x = 88.8888888888
88.8888888888 - x = 88 <----Right there
yes 88.88888 - x does = 88, but also, from earlier, we defined that 100x = 88.888888 also? you forgot that bit.
so, what we should have is
88.88888888 - x = 100x - x
you see how that works? because 88.88888888 and 100x ARE THE SAME THING, AS YOU DEFINED THAT YOURSELF EARLIER IN THE EQUATION
88.8888888888 / 88 = 1.0101010101 <-- that is also true, but a completely random equation unrelated to this in all but number content.
continuing that equation, 88 = 99x, x = 8/9, which is true.
This formula is how you get a fraction from a recurring decimal. IT'S JUST HOW IT IS. I presume you do art or something?
Originally posted by: drinkmorejava
Easy, NO, in order for the plane to take off, it must have a fast enough airspeed; as in how fast the air is going over the wings. If the conveyor belt is keeping the plane in the same place by going the opposite direction, there will be no displacement and thus, no air moving over the wings.
Originally posted by: letdown427
but 0.8888 doesn't equal one, so that would be impossible?
Originally posted by: letdown427
100x = 88.888888
subtract x from both sides.
99x = 88