RIDDLES! Or, are you smarter than the rest of us?

[BeeVo]

Originally posted by: cr4zymofo
Ok... so you're a tough guy, you roughed up some kids for lunch money and now you're behind bars on an island. This island is surrounded by lazers-on-head shark infested water, so swimming or crossing the water is out of the question, the bridge is only accessible by a 5 miles long bridge and at the center is a guard shack, maned by a big hairy monkey. The monkey's job is to guard against intruders and also tough guys like you that are trying to break out. The monkey's only weakness is epilepsy, it will fall asleep for a 3 mins period, and when it's awake, it will take you back to where you came from when it sees you. Assuming that you can run at the rate of 1 mile/min, how do you escape? (and no, this monkey is not tempted by your cheap bananas).

You wait for someone to come to your rescue because damn, you run a mile a minute and someone is bound to notice the mile a minute dude missing.

 

[merlocka]

Originally posted by: jaydee
Two people, named S and P, are talking about two numbers x and y.
(note: x and y are both integers greater than or equal to 2). S
knows their sum (x+y), while P knows their product (xy); however,
initially NEITHER knows x and y.

S: Hey P! I don't know what the numbers are.
P: I'm not surprised. I KNEW you didn't know. However, I too don't
know.
S: You don't? Really! Then I know what the numbers are!

What are the two numbers?

S not knowing what the numbers are means that the sum is any integer larger than 5, since S would know the sum if it's 4 (must be 2+2) or if it's 5 (must be 2+3).

P would know if it's like, 4 or 6 or 8 or 10 ... or 14 or any other Number which can only be broken into 4 roots (e.g. 1xR1xR2xNumber), but he tells S he doesn't know.

When S says he knows, that means it had to be a toss up between products of numbers who's sums have 2 solutions, but who's products only have 1 determinate value.

That narrows it down to
2+4 and 3+3, which have a sum of 6 and products of 8,9
2+5 and 3+4 which have a sum of 7 and products of 10,12

since P would know if it was 8 (must be 2x4) and if it were 9 (must be 3x3), S knows that the product must be 12 (which could be 3x4 or 2x6)

Since S would have known the sum if it were 3+4, it must be 2+6

so it's 2,6

sloppy methodology, but I got there somehow.

 

[merlocka]

Originally posted by: cr4zymofo
Ok... so you're a tough guy, you roughed up some kids for lunch money and now you're behind bars on an island. This island is surrounded by lazers-on-head shark infested water, so swimming or crossing the water is out of the question, the bridge is only accessible by a 5 miles long bridge and at the center is a guard shack, maned by a big hairy monkey. The monkey's job is to guard against intruders and also tough guys like you that are trying to break out. The monkey's only weakness is epilepsy, it will fall asleep for a 3 mins period, and when it's awake, it will take you back to where you came from when it sees you. Assuming that you can run at the rate of 1 mile/min, how do you escape? (and no, this monkey is not tempted by your cheap bananas).

Run 2.9 miles, then turn around and head towards the shack. Monkey will wake up, think you are an intruder, and take you back to where you "came from", e.g. the other side.

 

[XZeroII]

Originally posted by: jaydee
Two people, named S and P, are talking about two numbers x and y.
(note: x and y are both integers greater than or equal to 2). S
knows their sum (x+y), while P knows their product (xy); however,
initially NEITHER knows x and y.

S: Hey P! I don't know what the numbers are.
P: I'm not surprised. I KNEW you didn't know. However, I too don't
know.
S: You don't? Really! Then I know what the numbers are!

What are the two numbers?

Are you sure you aren't supposed to actually give the sum and/or product? That is REALLY vague.

 

[jaydee]

Originally posted by: merlocka

Originally posted by: jaydee
Two people, named S and P, are talking about two numbers x and y.
(note: x and y are both integers greater than or equal to 2). S
knows their sum (x+y), while P knows their product (xy); however,
initially NEITHER knows x and y.

S: Hey P! I don't know what the numbers are.
P: I'm not surprised. I KNEW you didn't know. However, I too don't
know.
S: You don't? Really! Then I know what the numbers are!

What are the two numbers?

S not knowing what the numbers are means that the sum is any integer larger than 5, since S would know the sum if it's 4 (must be 2+2) or if it's 5 (must be 2+3).

P would know if it's like, 4 or 6 or 8 or 10 ... or 14 or any other Number which can only be broken into 4 roots (e.g. 1xR1xR2xNumber), but he tells S he doesn't know.

When S says he knows, that means it had to be a toss up between products of numbers who's sums have 2 solutions, but who's products only have 1 determinate value.

That narrows it down to
2+4 and 3+3, which have a sum of 6 and products of 8,9
2+5 and 3+4 which have a sum of 7 and products of 10,12

since P would know if it was 8 (must be 2x4) and if it were 9 (must be 3x3), S knows that the product must be 12 (which could be 3x4 or 2x6)

Since S would have known the sum if it were 3+4, it must be 2+6

so it's 2,6

sloppy methodology, but I got there somehow.

I think you're incorrect. I don't have an "official" answer, but I came up with something different when I saw this. You're pretty close though.


Edit

Here's why: If it's 2 and 6, then the sum is 8 and the product is 12. Of course S doesn't know because it could be 4, 4 or 2, 6 or 5, 3. If the product doesn't know then it rules out 5, 3 because they are the only factors of 15; however, 4, 4 are not the only factors of 16 (2, 8) and 2, 6 are not the only factors of 12 (3, 4), so S still would not know.

 

[sygyzy]

Originally posted by: merlocka

Originally posted by: cr4zymofo
Ok... so you're a tough guy, you roughed up some kids for lunch money and now you're behind bars on an island. This island is surrounded by lazers-on-head shark infested water, so swimming or crossing the water is out of the question, the bridge is only accessible by a 5 miles long bridge and at the center is a guard shack, maned by a big hairy monkey. The monkey's job is to guard against intruders and also tough guys like you that are trying to break out. The monkey's only weakness is epilepsy, it will fall asleep for a 3 mins period, and when it's awake, it will take you back to where you came from when it sees you. Assuming that you can run at the rate of 1 mile/min, how do you escape? (and no, this monkey is not tempted by your cheap bananas).

Run 2.9 miles, then turn around and head towards the shack. Monkey will wake up, think you are an intruder, and take you back to where you "came from", e.g. the other side.

Good answer but that seems like it'd only be valid if it's a trick question. I wonder if it's right.

 

[sillymofo]

Originally posted by: sygyzy

Originally posted by: merlocka

Originally posted by: cr4zymofo Ok... so you're a tough guy, you roughed up some kids for lunch money and now you're behind bars on an island. This island is surrounded by lazers-on-head shark infested water, so swimming or crossing the water is out of the question, the bridge is only accessible by a 5 miles long bridge and at the center is a guard shack, maned by a big hairy monkey. The monkey's job is to guard against intruders and also tough guys like you that are trying to break out. The monkey's only weakness is epilepsy, it will fall asleep for a 3 mins period, and when it's awake, it will take you back to where you came from when it sees you. Assuming that you can run at the rate of 1 mile/min, how do you escape? (and no, this monkey is not tempted by your cheap bananas).

Run 2.9 miles, then turn around and head towards the shack. Monkey will wake up, think you are an intruder, and take you back to where you "came from", e.g. the other side.

Good answer but that seems like it'd only be valid if it's a trick question. I wonder if it's right.

He's right.

 

[HomeBrewerDude]

heres one off the top of my head... apologies if it sucks!

Most people only know one of my many faces.....
The sane and ordered side of me....
However, the depths of my irrational faces are limitless...
There is nothing I can't explain.
What am I????

 

[sygyzy]

Originally posted by: cr4zymofo

Originally posted by: sygyzy

Originally posted by: merlocka

Originally posted by: cr4zymofo Ok... so you're a tough guy, you roughed up some kids for lunch money and now you're behind bars on an island. This island is surrounded by lazers-on-head shark infested water, so swimming or crossing the water is out of the question, the bridge is only accessible by a 5 miles long bridge and at the center is a guard shack, maned by a big hairy monkey. The monkey's job is to guard against intruders and also tough guys like you that are trying to break out. The monkey's only weakness is epilepsy, it will fall asleep for a 3 mins period, and when it's awake, it will take you back to where you came from when it sees you. Assuming that you can run at the rate of 1 mile/min, how do you escape? (and no, this monkey is not tempted by your cheap bananas).

Run 2.9 miles, then turn around and head towards the shack. Monkey will wake up, think you are an intruder, and take you back to where you "came from", e.g. the other side.

Good answer but that seems like it'd only be valid if it's a trick question. I wonder if it's right.

He's right.

Then sorry, that's a bad riddle. It's more of a trick question.

 

[gsellis]

On the hat riddle, you are all wrong. Kid 3 is red-green color blind and they are facing a green board. He can't tell which ones are red and which are black. Kid 2 was misdiagnosed as ADD, so she is so doped up that she does not care. Kid 1 had a 50-50 shot and guessed.

 

[SmoiL]

Originally posted by: yamahaXS
heres one off the top of my head... apologies if it sucks!

Most people only know one of my many faces.....
The sane and ordered side of me....
However, the depths of my irrational faces are limitless...
There is nothing I can't explain.
What am I????

Something with math?

 

[gsellis]

Originally posted by: yamahaXS
heres one off the top of my head... apologies if it sucks!

Most people only know one of my many faces.....
The sane and ordered side of me....
However, the depths of my irrational faces are limitless...
There is nothing I can't explain.
What am I????

a clock, but it is all relative.

 

[HomeBrewerDude]

Originally posted by: SmoiL

Originally posted by: yamahaXS
heres one off the top of my head... apologies if it sucks!

Most people only know one of my many faces.....
The sane and ordered side of me....
However, the depths of my irrational faces are limitless...
There is nothing I can't explain.
What am I????

Something with math?

yep, pretty close. i was thinking of numbering systems.

 

[Insomniac]

Originally posted by: merlocka
Here is one.

2+11=1

I didn't see anyone answer this.

2+11=1 on a Clock.

 

[Insomniac]

Ok, here is one.

You work at a market and you sell flour by the pound from 1 to 40 in whole pounds. All you have is a balance scale and you only want to weigh the flour once per customer. You can purchase weights of any weight from 1 to 40 pounds in whole pounds. The weights are sold on a per weight basis, not by pound. What is the least number of weight(s) you need to purchase (along with their weight(s)) to sell your flour?

Edit: I screwed up. Added the bold text to fix it.

 

[MaxFusion16]

Originally posted by: Insomniac
Ok, here is one.

You work at a market and you sell flour by the pound from 1 to 40 in whole pounds. All you have is a balance scale. You can purchase weights of any weight from 1 to 40 pounds in whole pounds. The weights are sold on a per weight basis, not by pound. What is the least number of weight(s) you need to purchase (along with their weight(s)) to sell your flour?

one 1 pound weight
just measure the flour pound by pound

 

[Insomniac]

Originally posted by: MaxFusion16

Originally posted by: Insomniac
Ok, here is one.

You work at a market and you sell flour by the pound from 1 to 40 in whole pounds. All you have is a balance scale. You can purchase weights of any weight from 1 to 40 pounds in whole pounds. The weights are sold on a per weight basis, not by pound. What is the least number of weight(s) you need to purchase (along with their weight(s)) to sell your flour?

one 1 pound weight
just measure the flour pound by pound

You are right, but it just goes to show I messed up the riddle. I'll edit the original.

 

[yukichigai]

This one only works if someone tells you it. If you have the text here it spoils it.

A bus is going about its route, starting empty...
At the first stop, 12 people get on. At the next stop half get off, then 2/3rds as many that are on the bus get on. At the next stop 6 get on and the square root of that number get off. The next stop, nobody gets off, 4 get on. The next stop 5 people get off, 23 people get on. Then 15 people get off, 143 get on. Half of them get off at the next stop, 2 get on. Then 3/4ths of them get off at the next stop.









How many stops did the bus make?

 

[TuxDave]

Originally posted by: Insomniac
Ok, here is one.

You work at a market and you sell flour by the pound from 1 to 40 in whole pounds. All you have is a balance scale and you only want to weigh the flour once per customer. You can purchase weights of any weight from 1 to 40 pounds in whole pounds. The weights are sold on a per weight basis, not by pound. What is the least number of weight(s) you need to purchase (along with their weight(s)) to sell your flour?

Edit: I screwed up. Added the bold text to fix it.

I guess 6? I figure, if 1,2,4,8,16 can't do it.. and it seems to be the most efficient way of using only 5 bags, then I guess 6 will do with tons of different combinations like 1,2,4,8,16,32?

 

[TuxDave]

oooohooooo... i take back my answer.. gimme a sec.

 

[Amorphus]

Originally posted by: yukichigai
This one only works if someone tells you it. If you have the text here it spoils it.

A bus is going about its route, starting empty...
At the first stop, 12 people get on. At the next stop half get off, then 2/3rds as many that are on the bus get on. At the next stop 6 get on and the square root of that number get off. The next stop, nobody gets off, 4 get on. The next stop 5 people get off, 23 people get on. Then 15 people get off, 143 get on. Half of them get off at the next stop, 2 get on. Then 3/4ths of them get off at the next stop.



Two?





How many stops did the bus make?

 

[Insomniac]

Originally posted by: yukichigai
This one only works if someone tells you it. If you have the text here it spoils it.

A bus is going about its route, starting empty...
At the first stop, 12 people get on. At the next stop half get off, then 2/3rds as many that are on the bus get on. At the next stop 6 get on and the square root of that number get off. The next stop, nobody gets off, 4 get on. The next stop 5 people get off, 23 people get on. Then 15 people get off, 143 get on. Half of them get off at the next stop, 2 get on. Then 3/4ths of them get off at the next stop.









How many stops did the bus make?

That's a good one. I'll have to remember that.

 

[Insomniac]

Originally posted by: TuxDave
oooohooooo... i take back my answer.. gimme a sec.

It's been more than a second. You are right though, 6 is incorrect.

 

[jaydee]

Originally posted by: Insomniac
Ok, here is one.

You work at a market and you sell flour by the pound from 1 to 40 in whole pounds. All you have is a balance scale and you only want to weigh the flour once per customer. You can purchase weights of any weight from 1 to 40 pounds in whole pounds. The weights are sold on a per weight basis, not by pound. What is the least number of weight(s) you need to purchase (along with their weight(s)) to sell your flour?

Edit: I screwed up. Added the bold text to fix it.

I only worked this for a few minutes, but you can do it with 5 (maybe less?): 27, 13, 5, 3, 1.


Edit: Ya, I'm pretty sure 5 is the smallest number of weights.

 

[Insomniac]

Originally posted by: jaydee

Originally posted by: Insomniac
Ok, here is one.

You work at a market and you sell flour by the pound from 1 to 40 in whole pounds. All you have is a balance scale and you only want to weigh the flour once per customer. You can purchase weights of any weight from 1 to 40 pounds in whole pounds. The weights are sold on a per weight basis, not by pound. What is the least number of weight(s) you need to purchase (along with their weight(s)) to sell your flour?

Edit: I screwed up. Added the bold text to fix it.

I only worked this for a few minutes, but you can do it with 5 (maybe less?): 27, 13, 5, 3, 1.


Edit: Ya, I'm pretty sure 5 is the smallest number of weights.

That's incorrect.