Simple logic test

[Mark R]

You are presented with 4 cards. The cards have a letter on one side, and a number on the other side. They are laid in front of you as follows:

[*]A[*]B[*]1[*]2

Which cards must be flipped over in order to test the following statement:

If there is a vowel on one side, then there must be an odd number on the other side.

 

[Atomicus]

Flip the A?

 

[stan394]

A [EDIT:] and 2

 

[imported_LoKe]

I don't fscking understand.

 

[tjaisv]

can y be considered a vowel?

 

[pray4mojo]

nm didnt see poll

 

[torpid]

How can it be just A? What if there is an A on the other side of the 2?

 

[torpid]

Too many people picking A and 1. 1 is irrelevant. It can be A or B and the statement could still be true.

 

[GrantMeThePower]

It's A and 2

The statement ONLY says that u need to test wheather a card with a vowel on one side has a odd number. SO obviously u need to check the A, but then u need to make sure that the number 2 card DOESN"T have a vowel

 

[Slew Foot]

A and 2.

The B and 1 are irrelevant, you flip the A (vowel) to make sure there's an odd on the other side. You flip the 2 to make sure there is NOT a vowel on the other side.

 

[GrantMeThePower]

Originally posted by: Slew Foot
A and 2.

The B and 1 are irrelevant, you flip the A (vowel) to make sure there's an odd on the other side. You flip the 2 to make sure there is NOT a vowel on the other side.

Ha! Beat you by a minute. :thumbsup: props tho

 

[tjaisv]

he didn't say "card(s)", so it has to be more than 1

 

[etalns]

Originally posted by: Slew Foot
A and 2.

The B and 1 are irrelevant, you flip the A (vowel) to make sure there's an odd on the other side. You flip the 2 to make sure there is NOT a vowel on the other side.

It doesn't matter if there is a vowel on the other side of the 2, the statement can still remain true. It doesn't say that the others can NOT have a vowel on the other side, for example. You have to flip the 1 so you can check if the vowel is on the other side to prove it true. And you have to flip the A so you can see if the odd number is on the other side.

So you have to do A, 1, 2.

 

[etalns]

Originally posted by: GrantMeThePower

Originally posted by: Slew Foot
A and 2.

The B and 1 are irrelevant, you flip the A (vowel) to make sure there's an odd on the other side. You flip the 2 to make sure there is NOT a vowel on the other side.

Ha! Beat you by a minute. :thumbsup: props tho

Wrong, it doesn't say that cards that have a vowel on one side will NOT have an odd number on the other side, or conversely either.

 

[stan394]

Originally posted by: Qosis

Originally posted by: Slew Foot
A and 2.

The B and 1 are irrelevant, you flip the A (vowel) to make sure there's an odd on the other side. You flip the 2 to make sure there is NOT a vowel on the other side.

It doesn't matter if there is a vowel on the other side of the 2, the statement can still remain true. It doesn't say that the others can NOT have a vowel on the other side, for example. You have to flip the 1 so you can check if the vowel is on the other side to prove it true. And you have to flip the A so you can see if the odd number is on the other side.

if there is a vowel on the other side of 2, the statement is false.

 

[etalns]

Originally posted by: stan394

Originally posted by: Qosis

Originally posted by: Slew Foot
A and 2.

The B and 1 are irrelevant, you flip the A (vowel) to make sure there's an odd on the other side. You flip the 2 to make sure there is NOT a vowel on the other side.

It doesn't matter if there is a vowel on the other side of the 2, the statement can still remain true. It doesn't say that the others can NOT have a vowel on the other side, for example. You have to flip the 1 so you can check if the vowel is on the other side to prove it true. And you have to flip the A so you can see if the odd number is on the other side.

if there is a vowel on the other side of 2, the statement is false.

I just edited my last statement to add what I meant to add. They do have to check 1 though to make sure that there is a vowel on the other side.

 

[GrantMeThePower]

Originally posted by: Qosis

Originally posted by: Slew Foot
A and 2.

The B and 1 are irrelevant, you flip the A (vowel) to make sure there's an odd on the other side. You flip the 2 to make sure there is NOT a vowel on the other side.

It doesn't matter if there is a vowel on the other side of the 2, the statement can still remain true. It doesn't say that the others can NOT have a vowel on the other side, for example. You have to flip the 1 so you can check if the vowel is on the other side to prove it true. And you have to flip the A so you can see if the odd number is on the other side.

Wrong. You need to check number 2 becuase it says "If there is a vowel on one side, then there must be an odd number on the other side." which means "if there is a vowel on one side, then there must not be an even number because an even number is not an odd number" which means "if there is an even number it must NOT have a vowel on the other side" so you need to check number 2. You do NOT need to check number 1 because it doesn't say whether an odd can have a vowel or not, just that a vowel needs an odd number.

 

[torpid]

Originally posted by: Qosis

Originally posted by: Slew Foot
A and 2.

The B and 1 are irrelevant, you flip the A (vowel) to make sure there's an odd on the other side. You flip the 2 to make sure there is NOT a vowel on the other side.

It doesn't matter if there is a vowel on the other side of the 2, the statement can still remain true. It doesn't say that the others can NOT have a vowel on the other side, for example. You have to flip the 1 so you can check if the vowel is on the other side to prove it true. And you have to flip the A so you can see if the odd number is on the other side.

You are misreading it or just messing with people.

The 1 could have any letter and it could still be true that a vowel on one side means there is an odd number on the other.

The 2 can't have a vowel on the other side or the statement is false, because that would mean a vowel on one side does not mean an odd # on the other.

 

[stan394]

Originally posted by: Qosis

Originally posted by: Slew Foot
A and 2.

The B and 1 are irrelevant, you flip the A (vowel) to make sure there's an odd on the other side. You flip the 2 to make sure there is NOT a vowel on the other side.

It doesn't matter if there is a vowel on the other side of the 2, the statement can still remain true. It doesn't say that the others can NOT have a vowel on the other side, for example. You have to flip the 1 so you can check if the vowel is on the other side to prove it true. And you have to flip the A so you can see if the odd number is on the other side.

So you have to do A, 1, 2.

you don't need to check 1 because
- if there is a vowel on the other side, the statement is true
- if it is not a vowel on the other side, the statement is also true

 

[imported_LoKe]

I put all because...well...this logic question is retarded.

 

[GrantMeThePower]

Originally posted by: Qosis

Originally posted by: stan394

Originally posted by: Qosis

Originally posted by: Slew Foot
A and 2.

The B and 1 are irrelevant, you flip the A (vowel) to make sure there's an odd on the other side. You flip the 2 to make sure there is NOT a vowel on the other side.

It doesn't matter if there is a vowel on the other side of the 2, the statement can still remain true. It doesn't say that the others can NOT have a vowel on the other side, for example. You have to flip the 1 so you can check if the vowel is on the other side to prove it true. And you have to flip the A so you can see if the odd number is on the other side.

if there is a vowel on the other side of 2, the statement is false.

I just edited my last statement to add what I meant to add. They do have to check 1 though to make sure that there is a vowel on the other side.

Doesn't matter if number 1 has a vowel or not.

 

[jagec]

Originally posted by: GrantMeThePower
It's A and 2

The statement ONLY says that u need to test wheather a card with a vowel on one side has a odd number. SO obviously u need to check the A, but then u need to make sure that the number 2 card DOESN"T have a vowel

yup. easy.

 

[yhelothar]

A and 2

 

[tjaisv]

But what if there was a Y on the back of the 2?

 

[zimu]

A and 1 without a doubt, only those two can disprove the theory, which is all thats required.