Simple logic test

[jagec]

Originally posted by: AnonymouseUser
Nowhere does the statement state that their must not be a vowel behind an even number, just that there must be an odd number behind a vowel.

The only cards that need to be turned are A and 1.

If there is a vowel on one side, then there must be an odd number on the other side.

As long as paper has only 2 sides, if there is a vowel behind an even number, there is ALSO an even number behind a vowel, which violates the rule. Unless the OP stated "If a vowel is face-up, there must be an odd number on the other side", you have to consider both approaches.

And why do you think that 1 needs to be flipped?

 

[swtethan]

Originally posted by: Number1
It doesn?t mater what?s behind B and 2.
A and 1 must be tested to confirm statement: ?If there is a vowel on one side, then there must be an odd number on the other side?

Another way of saying it:. If there is an odd number on one side, then there must be a vowel on one side.

to confirm if its true, yes but to have a definate result all 4 have to be flipped

 

[Number1]

Originally posted by: swtethan
back of the cards
1
1
a
a


what are you gonna do now? right....

Wo asked about B and 2.
Flipping A and 1 prove the statement.

 

[AnonymouseUser]

Originally posted by: jagec

Originally posted by: AnonymouseUser
Nowhere does the statement state that their must not be a vowel behind an even number, just that there must be an odd number behind a vowel.

The only cards that need to be turned are A and 1.

If there is a vowel on one side, then there must be an odd number on the other side.

As long as paper has only 2 sides, if there is a vowel behind an even number, there is ALSO an even number behind a vowel, which violates the rule. Unless the OP stated "If a vowel is face-up, there must be an odd number on the other side", you have to consider both approaches.

And why do you think that 1 needs to be flipped?

I stand corrected. A and 2 it is.

 

[swai]

Originally posted by: xtknight
UNKNOWN (contrapositive) - If there is not an odd number on one side, then there must not be a vowel on the other side.

the contrapositive is KNOWN to be TRUE - wikipedia - contrapositive

so flip A and 2

 

[torpid]

It's really remarkable how many people think you have to flip 1 and almost as remarkable how many people think you DON'T have to flip 2.

 

[xtknight]

Alright, I'll try again. As if you guys wanted to read another long, boring, and probably wrong thesis. But here goes.

If there is a vowel on one side, then there must be an odd number on the other side.

*A: Alright, we have a vowel, one part of the equation. To prove the other part of the statement we must look at the other side of this 'A' card to see if there is an odd number behind it.

B: Nobody said anything about consonants so it doesn't need to be tested to prove anything. We don't even know what a consonant is or its relation to this subject.

*1: Alright, we have an odd number. Now we need to find out if there's a vowel on the other side, then we will know the statement is completely true.

2: Nobody said anything about even numbers so it doesn't need to be tested to prove anything.

Providing both A and 1 are TRUE the statement is true for those four exact cards.

Am I right now??!? What's the answer?!

 

[mugs]

http://en.wikipedia.org/wiki/Modus_ponens
http://en.wikipedia.org/wiki/Modus_tollens

 

[Number1]

Originally posted by: xtknight
Alright, I'll try again. As if you guys wanted to read another long, boring, and probably wrong thesis. But here goes.

If there is a vowel on one side, then there must be an odd number on the other side.

*A: Alright, we have a vowel, one part of the equation. To prove the other part of the statement we must look at the other side of this 'A' card to see if there is an odd number behind it.

B: Nobody said anything about consonants so it doesn't need to be tested to prove anything. We don't even know what a consonant is or its relation to this subject.

*1: Alright, we have an odd number. Now we need to find out if there's a vowel on the other side, then we will know the statement is completely true.

2: Nobody said anything about even numbers so it doesn't need to be tested to prove anything.

Providing both A and 1 are TRUE the statement is true for those four exact cards.

Am I right now??!? What's the answer?!

Good explanation!

 

[mugs]

Originally posted by: xtknight
Alright, I'll try again. As if you guys wanted to read another long, boring, and probably wrong thesis. But here goes.

If there is a vowel on one side, then there must be an odd number on the other side.

*A: Alright, we have a vowel, one part of the equation. To prove the other part of the statement we must look at the other side of this 'A' card to see if there is an odd number behind it.

B: Nobody said anything about consonants so it doesn't need to be tested to prove anything. We don't even know what a consonant is or its relation to this subject.

*1: Alright, we have an odd number. Now we need to find out if there's a vowel on the other side, then we will know the statement is completely true.

2: Nobody said anything about even numbers so it doesn't need to be tested to prove anything.

Providing both A and 1 are TRUE the statement is true for those four exact cards.

Am I right now??!? What's the answer?!

The correct answer is A and 2.

It says
If there is a vowel on one side, then there must be an odd number on the other side.

You know that you have to check A to make sure there's an odd number. What's behind 1 doesn't matter, because B & 1 wouldn't violate the condition. A & 2 would though, so you have to check what's behind 2.


If A is true, B is true.
B is true.
Is A true? We don't know.

If A is true, B is true.
A is true.
Is B true? YES

If A is true, B is true.
B is NOT true.
Is A true? Definitely NOT.

 

[Yossarian]

the pressure applied in teh topic summary was too much for my fragile little mind

 

[WolverineGator]

FYI, this is a very well known psychological test. It is well written about in the scientific literature. The OP threw out a red herring. It usually takes groups of college age students half an hour to come up with the correct solution.

 

[torpid]

Originally posted by: xtknight
Alright, I'll try again. As if you guys wanted to read another long, boring, and probably wrong thesis. But here goes.

If there is a vowel on one side, then there must be an odd number on the other side.

*A: Alright, we have a vowel, one part of the equation. To prove the other part of the statement we must look at the other side of this 'A' card to see if there is an odd number behind it.

B: Nobody said anything about consonants so it doesn't need to be tested to prove anything. We don't even know what a consonant is or its relation to this subject.

*1: Alright, we have an odd number. Now we need to find out if there's a vowel on the other side, then we will know the statement is completely true.

2: Nobody said anything about even numbers so it doesn't need to be tested to prove anything.

Providing both A and 1 are TRUE the statement is true for those four exact cards.

Am I right now??!? What's the answer?!

No, you are completely wrong.

Look at it his way:

If there is a consonant on the other side of 1 then it still can be true that "If there is a vowel on one side there is an odd number on the other". The statement does not say that there MUST be a vowel on the other side of an odd number, only that there must be an odd number on the other side of a vowel.

You have to check 2 because if there is a vowel on the other side of 2, then the statement is proven false. If you don't check 2 then you won't know if there is a vowel on the other side, therefore there is still some reasonable doubt as to the truth of the statement.

 

[Yossarian]

it doesn't matter what's on the other side of the 1.

 

[stan394]

Originally posted by: WolverineGator
FYI, this is a very well known psychological test. It is well written about in the scientific literature. The OP threw out a red herring. It usually takes groups of college age students half an hour to come up with the correct solution.

it isn't that hard if you took logic 101

 

[swtethan]

Originally posted by: Yossarian
it doesn't matter what's on the other side of the 1.

yes it does, because the facts state that there are 4 cards, one side has a letter, one side has a number. the hypothesis never says that the vowel has to be the face up card, just that the vowel is on one side and odd number on the other

but you still have to flip all 4 to get a final conclusion

flip 2 cards to get a half assed test

 

[PHiuR]

. flip A or 1...
then there will be either an A on one side or 1 on 1 side and vice versa.

 

[xtknight]

Originally posted by: swtethan

Originally posted by: Yossarian
it doesn't matter what's on the other side of the 1.

yes it does, because the facts state that there are 4 cards, one side has a letter, one side has a number. the hypothesis never says that the vowel has to be the face up card, just that the vowel is on one side and odd number on the other

Yeah, that's what I was thinking...

 

[swtethan]

Originally posted by: xtknight

Originally posted by: swtethan

Originally posted by: Yossarian
it doesn't matter what's on the other side of the 1.

yes it does, because the facts state that there are 4 cards, one side has a letter, one side has a number. the hypothesis never says that the vowel has to be the face up card, just that the vowel is on one side and odd number on the other

Yeah, that's what I was thinking...

this is why you have to check them all, anything could be on the backs of the cards to get a complete answer and not just a half answer with a and 1


if you turned in a half done english paper to your professor, do you expect to pass? no

 

[TuxDave]

Originally posted by: swtethan

Originally posted by: Yossarian
it doesn't matter what's on the other side of the 1.

yes it does, because the facts state that there are 4 cards, one side has a letter, one side has a number. the hypothesis never says that the vowel has to be the face up card, just that the vowel is on one side and odd number on the other

but you still have to flip all 4 to get a final conclusion

flip 2 cards to get a half assed test

What will you learn from flipping card B or card 1 in regards to proving the statement correct or incorrect? Nothing, so you don't need to flip it.

 

[TuxDave]

Originally posted by: swtethan

Originally posted by: xtknight

Originally posted by: swtethan

Originally posted by: Yossarian
it doesn't matter what's on the other side of the 1.

yes it does, because the facts state that there are 4 cards, one side has a letter, one side has a number. the hypothesis never says that the vowel has to be the face up card, just that the vowel is on one side and odd number on the other

Yeah, that's what I was thinking...

this is why you have to check them all, anything could be on the backs of the cards to get a complete answer and not just a half answer with a and 1


if you turned in a half done english paper to your professor, do you expect to pass? no

If I asked whether or not you had enough money to buy this $1 product, you don't have to count all the change in your pocket. If you count and halfway through you reach $1 you don't need to count anymore. You didn't finish counting but you didn't need to count anymore to determine your answer.

 

[Slew Foot]

Holy crap you people are stupid.

 

[swtethan]

Originally posted by: TuxDave

Originally posted by: swtethan

Originally posted by: Yossarian
it doesn't matter what's on the other side of the 1.

yes it does, because the facts state that there are 4 cards, one side has a letter, one side has a number. the hypothesis never says that the vowel has to be the face up card, just that the vowel is on one side and odd number on the other

but you still have to flip all 4 to get a final conclusion

flip 2 cards to get a half assed test

What will you learn from flipping card B or card 1 in regards to proving the statement correct or incorrect? Nothing, so you don't need to flip it.

what if B had a 1 on the back? what if 1 had an A on the back? there is nothing in the FACTS that states what is on the back of the cards except that its number on one side, letter on the other.

 

[stan394]

Originally posted by: swtethan

Originally posted by: TuxDave

Originally posted by: swtethan

Originally posted by: Yossarian
it doesn't matter what's on the other side of the 1.

yes it does, because the facts state that there are 4 cards, one side has a letter, one side has a number. the hypothesis never says that the vowel has to be the face up card, just that the vowel is on one side and odd number on the other

but you still have to flip all 4 to get a final conclusion

flip 2 cards to get a half assed test

What will you learn from flipping card B or card 1 in regards to proving the statement correct or incorrect? Nothing, so you don't need to flip it.

what if B had a 1 on the back? what if 1 had an A on the back? there is nothing in the FACTS that states what is on the back of the cards except that its number on one side, letter on the other.

what if B had a 1 on the back?
- it doesn't matter. it neither proves nor disproves the statement

what if 1 had an A on the back?
- it proves the statement, and same if 1 had a B on the back

 

[swtethan]

Originally posted by: TuxDave

Originally posted by: swtethan

Originally posted by: xtknight

Originally posted by: swtethan

Originally posted by: Yossarian
it doesn't matter what's on the other side of the 1.

yes it does, because the facts state that there are 4 cards, one side has a letter, one side has a number. the hypothesis never says that the vowel has to be the face up card, just that the vowel is on one side and odd number on the other

Yeah, that's what I was thinking...

this is why you have to check them all, anything could be on the backs of the cards to get a complete answer and not just a half answer with a and 1


if you turned in a half done english paper to your professor, do you expect to pass? no

If I asked whether or not you had enough money to buy this $1 product, you don't have to count all the change in your pocket. If you count and halfway through you reach $1 you don't need to count anymore. You didn't finish counting but you didn't need to count anymore to determine your answer.

thats not the same kind of problem


it has to be something like "you must have all quarters in your pocket" and lets say you have 4 coins in there but you dont know what they are, so are you just going to check 2 and say that its true?