Originally posted by: 5ayle
It's A, 1 and 2... B is irrelvant.
Originally posted by: Eeezee
- You require 1 because if there is a vowel on the other side, then the statement is true. If there is not a vowel on the other side, then the statement is false. It is absolutely necessary that you check this card because you don't know what letter is on the other side.
Originally posted by: Eeezee
You need A, 1, and 2.
- A is obvious. You know that it is a vowel, therefore you must check the other side for the number.
- You require 1 because if there is a vowel on the other side, then the statement is true. If there is not a vowel on the other side, then the statement is false. It is absolutely necessary that you check this card because you don't know what letter is on the other side.
- You require 2 because if there is a vowel on the other side, then the statement is false. Again, it is absolutely necessary to check this card because you don't know what letter is on the other side.
You are told that if a vowel is on one side, then an odd number must be on the other side. A consonant like B can have an odd number on the other side and the statement would still be true. We don't have to turn over B because the result is independent of whether our statement is true or not.
For the cards 1 and 2, we need to know what the letters are on the other side. In order for the statement to be true, we need to find a vowel on the other side of 1 and a consonant on the other side of 2. You can not logically deduce what exists on the other side of the card.
Here's another example with the same rule. You have 4 cards with the letter side facing up, A, E, B, and C. You would need to flip over the A and the E in order to verify the statement. You don't care about B and C because they are consonants and there is no rule for consonants. If you have 4 cards with the number side facing up, 1, 2, 3, and 4, then you would need to flip over all 4 cards in order to verify the statement. You don't know which cards have vowels and therefore you can't test your condition for any of the cards until you flip them.
Originally posted by: jagec
Originally posted by: Eeezee
- You require 1 because if there is a vowel on the other side, then the statement is true. If there is not a vowel on the other side, then the statement is false. It is absolutely necessary that you check this card because you don't know what letter is on the other side.
Untrue. There is no rule which states that consonants cannot have odd numbers on the other side, only that vowels must have them.
Originally posted by: her209
If there is a vowel on one side, then there must be an odd number on the other side.
The bolded must be true in order for the statement above to be true.
A - even/odd
B - even/odd
1 - consonant/vowel
2 - consonant/vowel
Originally posted by: Eeezee
Originally posted by: jagec
Originally posted by: Eeezee
- You require 1 because if there is a vowel on the other side, then the statement is true. If there is not a vowel on the other side, then the statement is false. It is absolutely necessary that you check this card because you don't know what letter is on the other side.
Untrue. There is no rule which states that consonants cannot have odd numbers on the other side, only that vowels must have them.
Yes, that's correct. Flipping the 1 could reveal a consonant or a vowel and the rule would still hold. Let me edit my post
Originally posted by: Schfifty Five
Originally posted by: Eeezee
You need A, 1, and 2.
- A is obvious. You know that it is a vowel, therefore you must check the other side for the number.
- You require 1 because if there is a vowel on the other side, then the statement is true. If there is not a vowel on the other side, then the statement is false. It is absolutely necessary that you check this card because you don't know what letter is on the other side.
- You require 2 because if there is a vowel on the other side, then the statement is false. Again, it is absolutely necessary to check this card because you don't know what letter is on the other side.
You are told that if a vowel is on one side, then an odd number must be on the other side. A consonant like B can have an odd number on the other side and the statement would still be true. We don't have to turn over B because the result is independent of whether our statement is true or not.
For the cards 1 and 2, we need to know what the letters are on the other side. In order for the statement to be true, we need to find a vowel on the other side of 1 and a consonant on the other side of 2. You can not logically deduce what exists on the other side of the card.
Here's another example with the same rule. You have 4 cards with the letter side facing up, A, E, B, and C. You would need to flip over the A and the E in order to verify the statement. You don't care about B and C because they are consonants and there is no rule for consonants. If you have 4 cards with the number side facing up, 1, 2, 3, and 4, then you would need to flip over all 4 cards in order to verify the statement. You don't know which cards have vowels and therefore you can't test your condition for any of the cards until you flip them.
You have shown that you do not understand conditional statments.
If 'A', then 'B'. Just b/c you are given 'B', that does not mean 'A' happens. We are not given enough info about what happens with B and frankly, we don't care what happens with 'B'.
Pertaining that to our topic. Just b/c we have a 1 showing, that does not mean the other side is a Vowel or consanant. In fact, it could be either and the conditional statement still holds true.
A & 2 ONLY.
Originally posted by: Eeezee
Originally posted by: Schfifty Five
Originally posted by: Eeezee
You need A, 1, and 2.
- A is obvious. You know that it is a vowel, therefore you must check the other side for the number.
- You require 1 because if there is a vowel on the other side, then the statement is true. If there is not a vowel on the other side, then the statement is false. It is absolutely necessary that you check this card because you don't know what letter is on the other side.
- You require 2 because if there is a vowel on the other side, then the statement is false. Again, it is absolutely necessary to check this card because you don't know what letter is on the other side.
You are told that if a vowel is on one side, then an odd number must be on the other side. A consonant like B can have an odd number on the other side and the statement would still be true. We don't have to turn over B because the result is independent of whether our statement is true or not.
For the cards 1 and 2, we need to know what the letters are on the other side. In order for the statement to be true, we need to find a vowel on the other side of 1 and a consonant on the other side of 2. You can not logically deduce what exists on the other side of the card.
Here's another example with the same rule. You have 4 cards with the letter side facing up, A, E, B, and C. You would need to flip over the A and the E in order to verify the statement. You don't care about B and C because they are consonants and there is no rule for consonants. If you have 4 cards with the number side facing up, 1, 2, 3, and 4, then you would need to flip over all 4 cards in order to verify the statement. You don't know which cards have vowels and therefore you can't test your condition for any of the cards until you flip them.
You have shown that you do not understand conditional statments.
If 'A', then 'B'. Just b/c you are given 'B', that does not mean 'A' happens. We are not given enough info about what happens with B and frankly, we don't care what happens with 'B'.
Pertaining that to our topic. Just b/c we have a 1 showing, that does not mean the other side is a Vowel or consanant. In fact, it could be either and the conditional statement still holds true.
A & 2 ONLY.
You have shown that you're an asshole. I already corrected myself. You could have done the same in nicer words.
Originally posted by: Mark R
You are presented with 4 cards. The cards have a letter on one side, and a number on the other side. They are laid in front of you as follows:
[*]A[*]B[*]1[*]2
Which cards must be flipped over in order to test the following statement:
If there is a vowel on one side, then there must be an odd number on the other side.
Originally posted by: Aquila76
Originally posted by: Mark R
You are presented with 4 cards. The cards have a letter on one side, and a number on the other side. They are laid in front of you as follows:
[*]A[*]B[*]1[*]2
Which cards must be flipped over in order to test the following statement:
If there is a vowel on one side, then there must be an odd number on the other side.
This phrasing makes any answer correct as any action could 'test' the statement. You're not asking for it to be 'proven', just 'tested'.
Originally posted by: chuckywang
A and 2!!!!!!!
Anybody who says otherwise doesn't know logic.