something I don't get from a C book that I am reading

[Onceler]

it says
int strlen(char s[])
{
int i;
i=0;
while (s!='\0')
++i;
return i;
}
the s wouldn't that be 0 since on the line before it it was declared that i=0;?

 

[nickbits]

i is an index. i=0 means it is starting at the first character. It increments the index with each iteration of the loop.

Also char s[] is the same as char* s

 

[Onceler]

Oh ok like it is pointing to element 0 of the array
thanks

 

[irishScott]

Oh ok like it is pointing to element 0 of the array
thanks

Not "like it", that's exactly what it is doing. Pointing and de-referencing.

array[0] = zeroth element of the array.
array[1] = first element of the array.

and so on.

 

[cytg111]

yea, and when there IS no '\0', the fun begins

 

[scragnoff]

It's saying - start from the start (zeroth element) of the string (or an array of characters) until you reach the end, which in this case is the null character ("\0"). i returns the length of that string.

 

[BRcr]

yea, and when there IS no '\0', the fun begins

C langugaes are funny ones, indeed. But in this case you would just get a wrong length.

 

[nickbits]

C langugaes are funny ones, indeed. But in this case you would just get a wrong length.

Or crash

 

[BRcr]

Don't think so. I actually tried reading all the memory I could reach. Crash happens when you try to modify there something.

 

[veri745]

Don't think so. I actually tried reading all the memory I could reach. Crash happens when you try to modify there something.

Yeah, the only way you would crash (or likely hang) is if there were no bytes in memory that were 0, which is fairly [extraordinarily] unlikely, and the loop would run infinitely.

 

[BRcr]

Exactly.