edit:
Solved.
Thanks for your help guys, and I got a response back from my teacher.
Here is what he says:
Hi Kevin, all you step are correct and from the last matrix you can
draw the conlusion, namely this system is always solvable for any b.
In fact you can read off the solution y=(b-4)/12 etc. ITI
Orig. Message
I have a test tomorrow and I'm not sure how to solve these types of problems. Someone please help
For which values of b the following linear system is consistent?
x - 3y = 2
2x + 6y = b
2x - 6y = 4
I can get the 12y = b - 4 from reducing the matrix, as I end up with:
[ 1 -3 2 ]
[ 0 12 b-4]
[ 0 0 0]
But how does this tell me which values of b this system is consistent. That's what I forget.
Solved.
Thanks for your help guys, and I got a response back from my teacher.
Here is what he says:
Hi Kevin, all you step are correct and from the last matrix you can
draw the conlusion, namely this system is always solvable for any b.
In fact you can read off the solution y=(b-4)/12 etc. ITI
Orig. Message
I have a test tomorrow and I'm not sure how to solve these types of problems. Someone please help
For which values of b the following linear system is consistent?
x - 3y = 2
2x + 6y = b
2x - 6y = 4
I can get the 12y = b - 4 from reducing the matrix, as I end up with:
[ 1 -3 2 ]
[ 0 12 b-4]
[ 0 0 0]
But how does this tell me which values of b this system is consistent. That's what I forget.