Originally posted by: So
-infinity
Originally posted by: coomar
isn't ln 0 equivalent to negative infinity
Originally posted by: coomar
well i visualize y=e^x and it only approaches zero at negative infinitity
Originally posted by: jman19
Originally posted by: coomar
isn't ln 0 equivalent to negative infinity
I do believe that it is defined as that... but more acurately, ln x approaches -inf as x approaches 0+... x=0 is an asymptote of the function ln x, so I don't think it's valid to say that the solution is ln(0)... though I most definitely may be wrong
Originally posted by: Eeezee
Originally posted by: jman19
Originally posted by: coomar
isn't ln 0 equivalent to negative infinity
I do believe that it is defined as that... but more acurately, ln x approaches -inf as x approaches 0+... x=0 is an asymptote of the function ln x, so I don't think it's valid to say that the solution is ln(0)... though I most definitely may be wrong
You're completely right
Originally posted by: chuckywang
Someone find a solution to ze^z = -1.
Originally posted by: Bigsm00th
actually the answer is e^(i*pi) = 0
Originally posted by: Bigsm00th
actually the answer is e^(i*pi) = 0