The most interesting math problem I've seen in a long time

[stan394]

Originally posted by: KMDupont64
http://www.csh.rit.edu/~pat/math/quickies/epii/

http://mathforum.org/library/drmath/view/51921.html

yeah we all know e^(i*pi) = -1 but the damn OP is saying that e^z = 0 and it's possible to solve for z, and we are all scratching our heads.

 

[MrDudeMan]

Originally posted by: KMDupont64
http://www.csh.rit.edu/~pat/math/quickies/epii/

http://mathforum.org/library/drmath/view/51921.html

what did either of those links prove? most of the people in this thread already knew everything those links had to offer if you had bothered to read before posting.

 

[ForumMaster]

the one answer to life and any math problem in exsistence: 42! lol

 

[archcommus]

TI-89 says no solution!

 

[Jack Ryan]

Originally posted by: Bigsm00th

Originally posted by: KMDupont64
http://www.csh.rit.edu/~pat/math/quickies/epii/

http://mathforum.org/library/drmath/view/51921.html

what did either of those links prove? most of the people in this thread already knew everything those links had to offer if you had bothered to read before posting.

I am sorry my post upset you kind sir. It was only meant to help the mere mortals that may not have known about it.

 

[MrDudeMan]

Originally posted by: KMDupont64

Originally posted by: Bigsm00th

Originally posted by: KMDupont64
http://www.csh.rit.edu/~pat/math/quickies/epii/

http://mathforum.org/library/drmath/view/51921.html

what did either of those links prove? most of the people in this thread already knew everything those links had to offer if you had bothered to read before posting.

I am sorry my post upset you kind sir. It was only meant to help the mere mortals that may not have known about it.

i didnt mean to sound so rude. sorry about that.

 

[Jack Ryan]

Originally posted by: Bigsm00th

Originally posted by: KMDupont64

Originally posted by: Bigsm00th

Originally posted by: KMDupont64
http://www.csh.rit.edu/~pat/math/quickies/epii/

http://mathforum.org/library/drmath/view/51921.html

what did either of those links prove? most of the people in this thread already knew everything those links had to offer if you had bothered to read before posting.

I am sorry my post upset you kind sir. It was only meant to help the mere mortals that may not have known about it.

i didnt mean to sound so rude. sorry about that.

It's cool, no worries.

 

[DaShen]

Originally posted by: chuckywang
Someone find a solution to ze^z = -1.

Imaginary number

 

[DaShen]

Originally posted by: chuckywang
Someone find a solution to ze^z = -1.

Imaginary number

 

[MrDudeMan]

how lame...we got spidered for sure

 

[tikwanleap]

Originally posted by: Bigsm00th
how lame...we got spidered for sure

Maybe he realized that there is no answer and spidered us.

<Golem Voice>Master spidered us!</Golem Voice>

 

[Soccer55]

Originally posted by: tikwanleap

Originally posted by: Bigsm00th
how lame...we got spidered for sure

Maybe he realized that there is no answer and spidered us.

<Golem Voice>Master spidered us!</Golem Voice>

-Tom

 

[MrDudeMan]

Originally posted by: Soccer55

Originally posted by: tikwanleap

Originally posted by: Bigsm00th
how lame...we got spidered for sure

Maybe he realized that there is no answer and spidered us.

<Golem Voice>Master spidered us!</Golem Voice>

-Tom

how annoying...i was hoping it was some cool trick.

 

[coomar]

spidered us?

 

[overst33r]

e^iTHETA = cisTHETA
abs(cisTHETA)=1
cosTHETA+isinTHETA cannot equal 0

No solution exists!

 

[DVK916]

There is no solution. His plan worked. He wanted to get people to spend time trying to solve a problem that has no solution.

 

[stan394]

Originally posted by: DVK916
There is no solution. His plan worked. He wanted to get people to spend time trying to solve a problem that has no solution.

I vote for a ban

 

[stan394]

Originally posted by: stan394

Originally posted by: DVK916
There is no solution. His plan worked. He wanted to get people to spend time trying to solve a problem that has no solution.

I vote for a ban

seconded

 

[stan394]

Originally posted by: stan394

Originally posted by: stan394

Originally posted by: DVK916
There is no solution. His plan worked. He wanted to get people to spend time trying to solve a problem that has no solution.

I vote for a ban

seconded

thirded

 

[overst33r]

Originally posted by: stan394

Originally posted by: stan394

Originally posted by: stan394

Originally posted by: DVK916
There is no solution. His plan worked. He wanted to get people to spend time trying to solve a problem that has no solution.

I vote for a ban

seconded

thirded

quadforthed

 

[DVK916]

Originally posted by: stan394

Originally posted by: stan394

Originally posted by: stan394

Originally posted by: DVK916
There is no solution. His plan worked. He wanted to get people to spend time trying to solve a problem that has no solution.

I vote for a ban

seconded

thirded

:laugh:

 

[TheRyuu]

Originally posted by: mariok2006

Originally posted by: stan394

Originally posted by: stan394

Originally posted by: stan394

Originally posted by: DVK916
There is no solution. His plan worked. He wanted to get people to spend time trying to solve a problem that has no solution.

I vote for a ban

seconded

thirded

quadforthed

what ever the hell is for fifth (fifthed?)

Edit: Now show us the dam solution if you have one! :|

 

[RaynorWolfcastle]

The real question is:
does e^(0.99999...) = e?

 

[DVK916]

Notice how he no longer post in this thread.

 

[Xonoahbin]

Could it be.... -1^-0????????
-0 might sound like "that's impossible," but I'm going to go ahead and use that

I'm getting e=1..
so

1^(-1^-0) = 0
1^-1^-0

^-1 implies that a number will be multiplied by itself negatively, so 1^-1 will be -1, then the -0 exponent will take the form an exponent zero takes (x1) and a -0 will have different properties, therefore maybe canceling?

I've never seen a -0, but I thought of it like "Hey, maybe?"
Maybe